# Non-responsive UI thread detected. Stack saved at ... But I couldn't find where exactly

**URL:** <https://forum.inductiveautomation.com/t/non-responsive-ui-thread-detected-stack-saved-at-but-i-couldnt-find-where-exactly/116073>\
**Category:** Ignition\
**Tags:** ignition81, scripting, vision\
**Created:** [June 19, 2026, 8:42am UTC](https://forum.inductiveautomation.com/t/non-responsive-ui-thread-detected-stack-saved-at-but-i-couldnt-find-where-exactly/116073 "2026-06-19T08:42:21Z")\
**Posts on this page:** 1\
**Showing post:** 5

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**Author:** ![pturmel](https://sea1.discourse-cdn.com/inductiveautomation/user_avatar/forum.inductiveautomation.com/pturmel/32/3295_2.png) [@pturmel](https://forum.inductiveautomation.com/u/pturmel)\
**Post date:** [June 19, 2026, 7:29pm UTC](https://forum.inductiveautomation.com/t/non-responsive-ui-thread-detected-stack-saved-at-but-i-couldnt-find-where-exactly/116073/5 "2026-06-19T19:29:44Z")

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Deep discussion here:

> [@Update GUI via Asynchronous thread](https://forum.inductiveautomation.com/t/update-gui-via-asynchronous-thread/9666):
>
> I’ve got a script I am experimenting with that can take a lot of time to execute, so I now use the system.util.invokeAsynchronous to run the script in a separate thread to keep the GUI from locking up. I am using the asynchronous thread to copy files from one place to another, and I would like to show the progress of the file copy with a progress bar. How would I go about this? I am importing a few python libraries to do this. import shutil def fileTransfer(): path = system.file.openFile() …

Yes, old but still applicable.

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