Omron FINS Driver String Byte Order

[David_Stone]

String Format byte order

Just so you don’t scratch your head for too long on this: s = "eRicep1 32" s = ''.join(c for pair in zip(s[1::2], s[::2]) for c in pair) s[1::2] and s[::2] will produce strings with even or odd characters ([1::2] = start from 1, stop at the end, step 2), zip will take one character from each, then it’s simply a matter of putting things in the right order. So, with "eRicep1 32", s[1::2] will be "Rcp 2" and s[::2] "eie13" zip("Rcp 2", "eie13") produces the pairs [('R', 'e'), ('c', 'i'), ('p'…

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