Simple xml parsing question

[pturmel]

Related:

Download file as xml

Good morning Gerardo, Yes, but you'll have to generate the XML piece by piece. I would use my helper script module for this kind of work: xml.py (Place it in your project script library.) Make a somewhat generic row-to-xml function in a project library, perhaps like so: rowTemplate = """<table><row/></table>""" # Produce downloadable XML bytes from a dictionary of column values. def rowToXML(valuesDict): dom = xml.strToDoc(rowTemplate) rowNode = dom.getElementsByTagName("row")[0] for k, …

I highly recommend using my wrappers around java's native XML handlers.

Edit: This might be more helpful:

New conversion from python parsing to Java

Here is the current block of code where I am using the parse with jython solution that tends to lock up every so often. import xml.etree.ElementTree as ET #read the xml filef for device in importDevices: filePath = '%s/%s.xml' % (rootPath,device) #print 'reading %s' % filePath deviceStart = system.date.now() #logger.info('Before: tree = ET.parse(filePath)') tree = ET.parse(filePath) #logger.info('After: tree = ET.parse(filePath)') xmlFile = tree.getroot() I made the f…