Write 2 diff values of the same property inside a script

Ignition
1

I try to write a property of a component to the value 1
on the start of a button action performed script,
and to the value 0 at the end.

This component is used for displaying a wait message.

The value stay to 0, and the message is not displayed.
Is it possible to write 2 different values of the same property, or of a same client tag,
inside the same script ?

2

Are those 0 and 1 values the value that determines if the message is showing or not? Are you trying to display the wait message for a set period of time? What exactly are you trying to do with the message box?

3

Yes the value determine if the label message is visible or not, the code is the following :

[code]import app.commun
import app.bdd
import system

event.source.parent.getComponent(‘LabelWait’).visible = 1
event.source.componentEnabled=0

liste des tables PG

sql = “SELECT TABLE_NAME FROM INFORMATION_SCHEMA.TABLES where table_type=‘TABLE’ order by TABLE_NAME asc”
result = system.db.runQuery(sql,dbfrontal)

listeCpt = []
for res in result:
nom_table = res[0]
cpt = system.db.runScalarQuery("SELECT COUNT(*) FROM " + nom_table,dbfrontal)
listeCpt.append([nom_table,cpt]);

sql = “SELECT TABLE_NAME FROM INFORMATION_SCHEMA.TABLES where table_type=‘VIEW’ order by TABLE_NAME asc”
result = system.db.runQuery(sql,dbfrontal)
for res in result:
nom_table = res[0]
listeCpt.append([nom_table,0]);

headers = [“Table”, “Nombre Enregistrements”]
result = system.dataset.toDataSet(headers,listeCpt)
event.source.parent.getComponent(‘Table’).data = result

event.source.componentEnabled=1
event.source.parent.getComponent(‘LabelWait’).visible = 0[/code]

import system

event.source.parent.getComponent('LabelWait').visible = 1
event.source.componentEnabled=0

... long duration process....

event.source.componentEnabled=1
event.source.parent.getComponent('LabelWait').visible = 0
4

I do this in two parts. In the action script attached to the button I change the cursor to the wait one first and then I call the long running script.

At the end of the script I restore the cursor with system.util.invokeLater()

5

Thanks Robert.

I found a similar solution in the doc :

[code]def longProcess(rootContainer = event.source.parent):

import system

…

# Now we'll send our results back to the UI
def sendBack(result = result,rootContainer = rootContainer):
	import system		
	rootContainer.getComponent('Table').data = result
	system.tag.write("[Client]busy",0)
system.util.invokeLater(sendBack)

system.tag.write("[Client]busy",1)
system.util.invokeAsynchronous(longProcess)[/code]

the only drawback is the use of sendback method which is a bit tricky to integrate in existing code

6

Yeah, I was going to suggest invokeAsynchronous/invokeLater - essential if you’re trying to work with both long-running tasks and the UI.